Question 2902
{"accessible":false,"alternatives":[{"id":14147,"text":".20"},{"id":14148,"text":".30"},{"id":14149,"text":".40"},{"id":14150,"text":".50"},{"id":14151,"text":".60"}],"archived":false,"correctAlternativeId":14150,"explanation":"\u003cp\u003eThe formula for odds is the probability (event) / (1-probability (event)), therefore, odds = P(4 or 5) / (1-P(4 or 5)) = (2/6) / (1-2/6) = (1/3) / (2/3) =.50\u003c/p\u003e","id":2902,"imageUrl":null,"imageAttribution":null,"imageAttributionCaseInfo":null,"firstQuestionPath":"/questions/2914","nextQuestionPath":null,"relatedArticles":[],"alsoUsedIn":[{"id":1913,"kind":"Course","title":"Papa \u0026 Papa Bear's Medical Statistics Short Course - page 1913","link":"https://radiopaedia.org/courses/medical-statistics-short-course/pages/1913"}],"stem":"\u003cp\u003eWhat are the odds of rolling a 4 or a 5 with a fair 6-sided die?\u003c/p\u003e","menuLinks":[{"text":"Report problem with question","url":"https://docs.google.com/forms/d/e/1FAIpQLSfO3soWYhOjJ7yErSysyCe5V4A1CqW7WK3rDA7MtAkecMGqNw/viewform?entry.1624461248\u0026entry.553583435=https://radiopaedia.org/questions/2902"}],"attemptsPercentages":[{"alternativeId":"14148","percentage":44},{"alternativeId":"14149","percentage":11},{"alternativeId":"14150","percentage":33},{"alternativeId":"14151","percentage":11},{"alternativeId":"14147","percentage":0}],"promptToLogin":false,"questionManager":false,"articleId":"probability-vs-odds"}